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 A334991 a(n) = 4^n + 3 * 18^n. 0
 4, 58, 988, 17560, 315184, 5669728, 102040768, 1836676480, 33059947264, 595078133248, 10711402728448, 192805234432000, 3470494161055744, 62468894664122368, 1124440103014678528, 20239921850506117120, 364318593294077722624, 6557734679233269465088, 118039224225958332203008 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,1 COMMENTS This sequence is a variation of the sequence A333385, variation proposed by Tony Gardiner in his book in reference. Proposition: a(n) is a perfect square iff n = 0; in this case, a(0) = 4. REFERENCES A. Gardiner, The Mathematical Olympiad Handbook: An Introduction to Problem Solving, Oxford University Press, 1997, reprinted 2011, page 115 (1991). LINKS Table of n, a(n) for n=0..18. Index entries for linear recurrences with constant coefficients, signature (22,-72). FORMULA a(n) = A000302(n) + 3 * A001027(n). a(n) = 22*a(n-1) - 72*a(n-2) for n>1. G.f.: (4 - 30*x)/((1 - 4*x)*(1 - 18*x)). - Alejandro J. Becerra Jr., Jun 01 2020 EXAMPLE a(4) = 4^4 + 3 * 18^4 = 315184 = 2^4 * 19699 is not a perfect square. MAPLE S:=seq(4^n+3*18^n, n=0..20); CROSSREFS Cf. A000302, A001027, A333385. Sequence in context: A197177 A155668 A240430 * A216795 A216352 A295406 Adjacent sequences: A334988 A334989 A334990 * A334992 A334993 A334994 KEYWORD nonn,easy AUTHOR Bernard Schott, May 18 2020 STATUS approved

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Last modified September 26 20:30 EDT 2023. Contains 365668 sequences. (Running on oeis4.)