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A331813 a(n) is the least k > 1 such that k*A019278(n) belongs to A019278 too, or a(n) = 0 if no such k exists. 0
2, 2, 2, 2, 4, 4, 2, 7, 2, 4, 8, 2, 3, 2, 2, 4, 2, 64, 3, 64, 4, 8, 7, 4, 15, 3, 50, 2, 2, 50, 2, 7, 29184, 2, 16, 64, 4, 16, 4, 385, 15, 9, 313600, 2, 4, 2793, 4199, 2, 4, 57600 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
COMMENTS
For the 132 terms (< 5*10^11) of the b-file for A019278, and using an extended list of terms, it can be checked that a(n) is not 0, even if the precise value is not known. For instance, a(51) <= 8097830664651.
Then a(52) to a(82) are: 4, 9, 1197, 8, 256, 4, 65155475, 64, 4096, 16, 195205791, 1387, 7, 37791, 4, 119, 8, 35136, 225, 64, 69127695, 2129920, 256, 4, 19671223, 9, 2, 1379763, 8, 90, 4096. And a(83) <= 7758260899200.
a(51) and a(83) are > 10^9.
LINKS
EXAMPLE
With A019278 starting as 1, 2, 4, 8, 15, 16, 21, 24, 42, 60, 64, ...
one gets the proper multiples 2, 4, 8, 16, 60, 64, ...
and so the sequence begins: 2, 2, 2, 2, 4, 4, ...
PROG
(PARI) a(n, v019278) = my(m = v019278[n]); my(k=2, y = k*m); while (denominator(sigma(sigma(y))/y) != 1, k++; y += m); k;
CROSSREFS
Cf. A019278 (integers m such that sigma(sigma(m))/m is an integer).
Sequence in context: A074912 A274207 A158502 * A215244 A195427 A006643
KEYWORD
nonn,more
AUTHOR
Michel Marcus, Jan 27 2020
STATUS
approved

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Last modified April 19 15:34 EDT 2024. Contains 371794 sequences. (Running on oeis4.)