A329362 Length of the co-Lyndon factorization of the first n terms of A000002.

0, 1, 2, 3, 2, 2, 3, 2, 3, 4, 3, 4, 5, 4, 3, 4, 3, 3, 4, 5, 4, 5, 3, 3, 4, 3, 4, 5, 4, 3, 4, 3, 3, 4, 3, 4, 5, 4, 5, 6, 5, 4, 5, 4, 5, 6, 5, 6, 4, 4, 5, 4, 4, 5, 6, 5, 6, 7, 6, 5, 6, 5, 6, 7, 6, 7, 8, 7, 6, 7, 6, 5, 6, 5, 6, 7, 6, 7, 5, 5, 6, 7, 6, 7, 8, 7, 6, 7

Offset

0,3

Comments

The co-Lyndon product of two or more finite sequences is defined to be the lexicographically minimal sequence obtainable by shuffling the sequences together. For example, the co-Lyndon product of (231) and (213) is (212313), the product of (221) and (213) is (212213), and the product of (122) and (2121) is (1212122). A co-Lyndon word is a finite sequence that is prime with respect to the co-Lyndon product. Equivalently, a co-Lyndon word is a finite sequence that is lexicographically strictly greater than all of its cyclic rotations. Every finite sequence has a unique (orderless) factorization into co-Lyndon words, and if these factors are arranged in a certain order, their concatenation is equal to their co-Lyndon product. For example, (1001) has sorted co-Lyndon factorization (1)(100).

Links

Table of n, a(n) for n=0..87.

Example

The co-Lyndon factorizations of the initial terms of A000002:
                      () = 0
                     (1) = (1)
                    (12) = (1)(2)
                   (122) = (1)(2)(2)
                  (1221) = (1)(221)
                 (12211) = (1)(2211)
                (122112) = (1)(2211)(2)
               (1221121) = (1)(221121)
              (12211212) = (1)(221121)(2)
             (122112122) = (1)(221121)(2)(2)
            (1221121221) = (1)(221121)(221)
           (12211212212) = (1)(221121)(221)(2)
          (122112122122) = (1)(221121)(221)(2)(2)
         (1221121221221) = (1)(221121)(221)(221)
        (12211212212211) = (1)(221121)(2212211)
       (122112122122112) = (1)(221121)(2212211)(2)
      (1221121221221121) = (1)(221121)(221221121)
     (12211212212211211) = (1)(221121)(2212211211)
    (122112122122112112) = (1)(221121)(2212211211)(2)
   (1221121221221121122) = (1)(221121)(2212211211)(2)(2)
  (12211212212211211221) = (1)(221121)(2212211211)(221)

Mathematica

kolagrow[q_]:=If[Length[q]<2, Take[{1, 2}, Length[q]+1], Append[q, Switch[{q[[Length[Split[q]]]], q[[-2]], Last[q]}, {1, 1, 1}, 0, {1, 1, 2}, 1, {1, 2, 1}, 2, {1, 2, 2}, 0, {2, 1, 1}, 2, {2, 1, 2}, 2, {2, 2, 1}, 1, {2, 2, 2}, 1]]]
kol[n_Integer]:=If[n==0, {}, Nest[kolagrow, {1}, n-1]];
colynQ[q_]:=Array[Union[{RotateRight[q, #], q}]=={RotateRight[q, #], q}&, Length[q]-1, 1, And];
colynfac[q_]:=If[Length[q]==0, {}, Function[i, Prepend[colynfac[Drop[q, i]], Take[q, i]]]@Last[Select[Range[Length[q]], colynQ[Take[q, #]]&]]];
Table[Length[colynfac[kol[n]]], {n, 0, 100}]

Crossrefs

The non-"co" version is A296658.

Cf. A000002, A001037, A060223, A088568, A102659, A275692, A329312, A329315, A329317, A329318.

Sequence in context: A085239 A374369 A242872 * A372971 A241604 A282900

Adjacent sequences: A329359 A329360 A329361 * A329363 A329364 A329365

Keyword

nonn

Author

Gus Wiseman, Nov 12 2019

Status

approved