

A326692


Values of n for which the denominator of (Sum_{prime p  n} 1/p  1/n) is n.


3



1, 4, 8, 9, 15, 16, 20, 24, 25, 27, 28, 32, 33, 35, 36, 40, 44, 45, 49, 51, 52, 60, 63, 64, 65, 68, 69, 72, 76, 77, 81, 85, 87, 88, 91, 92, 95, 96, 99, 100, 104, 108, 112, 115, 116, 117, 119, 121, 123, 124, 125, 128, 133, 135, 136, 140, 141, 143, 144, 145, 148
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OFFSET

1,2


COMMENTS

Any prime power p^k with k > 1 is a term, as 1/p  1/p^k = (p^(k1)  1)/p^k which is in reduced form and has denominator p^k.
Are there infinitely many Carmichael numbers A002997 in the sequence?


LINKS

Table of n, a(n) for n=1..61.


FORMULA

Solutions of A326690(x) = x. That is, fixed points of A326690.


EXAMPLE

1/3 + 1/5  1/15 = 7/15 has denominator 15, so 15 is a term.


MATHEMATICA

PrimeFactors[n_] := Select[Divisors[n], PrimeQ];
f[n_] := Denominator[Sum[1/p, {p, PrimeFactors[n]}]  1/n];
Select[Range[148], f[#] == # &]


CROSSREFS

Cf. A002997, A326689, A326690, A326691, A326715.
Sequence in context: A280450 A137055 A078177 * A336663 A329936 A023886
Adjacent sequences: A326689 A326690 A326691 * A326693 A326694 A326695


KEYWORD

nonn


AUTHOR

Jonathan Sondow, Jul 20 2019


STATUS

approved



