OFFSET
1,1
COMMENTS
If any odd perfect number exists, then it must occur in this sequence.
LINKS
PROG
(PARI)
A001065(n) = (sigma(n)-n);
isA228058(n) = if(!(n%2)||(omega(n)<2), 0, my(f=factor(n), y=0); for(i=1, #f~, if(1==(f[i, 2]%4), if((1==y)||(1!=(f[i, 1]%4)), return(0), y=1), if(f[i, 2]%2, return(0)))); (y));
k=0; n=0; while(k<100, n++; if(isA228058(n)&&isA228058(A001065(n)), k++; print1(n, ", ")));
CROSSREFS
KEYWORD
nonn
AUTHOR
Antti Karttunen, Apr 22 2019
STATUS
approved