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A309049
Number T(n,k) of (binary) max-heaps on n elements from the set {0,1} containing exactly k 0's; triangle T(n,k), n>=0, 0<=k<=n, read by rows.
18
1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 2, 2, 1, 1, 1, 3, 3, 2, 1, 1, 1, 3, 4, 4, 2, 1, 1, 1, 4, 6, 6, 5, 2, 1, 1, 1, 4, 7, 8, 7, 5, 2, 1, 1, 1, 5, 10, 12, 11, 8, 5, 2, 1, 1, 1, 5, 11, 16, 17, 13, 9, 5, 2, 1, 1, 1, 6, 15, 23, 27, 24, 16, 10, 5, 2, 1, 1, 1, 6, 16, 27, 34, 34, 27, 18, 11, 5, 2, 1, 1
OFFSET
0,8
COMMENTS
Also the number T(n,k) of (binary) min-heaps on n elements from the set {0,1} containing exactly k 1's.
The sequence of column k satisfies a linear recurrence with constant coefficients of order A063915(k).
LINKS
Eric Weisstein's World of Mathematics, Heap
Wikipedia, Binary heap
FORMULA
Sum_{k=0..n} k * T(n,k) = A309051(n).
Sum_{k=0..n} (n-k) * T(n,k) = A309052(n).
Sum_{k=0..2^n-1} T(2^n-1,k) = A003095(n+1).
Sum_{k=0..2^n-1} (2^n-1-k) * T(2^n-1,k) = A024358(n).
Sum_{k=0..n} (T(n,k) - T(n-1,k)) = A168542(n).
T(m,m-n) = A000108(n) for m >= 2^n-1 = A000225(n).
T(2^n-1,k) = A202019(n+1,k+1).
EXAMPLE
T(6,0) = 1: 111111.
T(6,1) = 3: 111011, 111101, 111110.
T(6,2) = 4: 110110, 111001, 111010, 111100.
T(6,3) = 4: 101001, 110010, 110100, 111000.
T(6,4) = 2: 101000, 110000.
T(6,5) = 1: 100000.
T(6,6) = 1: 000000.
T(7,4) = T(7,7-3) = A000108(3) = 5: 1010001, 1010010, 1100100, 1101000, 1110000.
Triangle T(n,k) begins:
1;
1, 1;
1, 1, 1;
1, 2, 1, 1;
1, 2, 2, 1, 1;
1, 3, 3, 2, 1, 1;
1, 3, 4, 4, 2, 1, 1;
1, 4, 6, 6, 5, 2, 1, 1;
1, 4, 7, 8, 7, 5, 2, 1, 1;
1, 5, 10, 12, 11, 8, 5, 2, 1, 1;
1, 5, 11, 16, 17, 13, 9, 5, 2, 1, 1;
1, 6, 15, 23, 27, 24, 16, 10, 5, 2, 1, 1;
1, 6, 16, 27, 34, 34, 27, 18, 11, 5, 2, 1, 1;
...
MAPLE
b:= proc(n) option remember; `if`(n=0, 1, (g-> (f-> expand(
x^n+b(f)*b(n-1-f)))(min(g-1, n-g/2)))(2^ilog2(n)))
end:
T:= n-> (p-> seq(coeff(p, x, i), i=0..n))(b(n)):
seq(T(n), n=0..14);
MATHEMATICA
b[n_] := b[n] = If[n == 0, 1, Function[g, Function[f, Expand[x^n + b[f]*b[n - 1 - f]]][Min[g - 1, n - g/2]]][2^Floor[Log[2, n]]]];
T[n_] := Function[p, Table[Coefficient[p, x, i], {i, 0, n}]][b[n]];
T /@ Range[0, 14] // Flatten (* Jean-François Alcover, Oct 04 2019, after Alois P. Heinz *)
CROSSREFS
Columns k=0-10 give: A000012, A110654, A114220 (for n>0), A326504, A326505, A326506, A326507, A326508, A326509, A326510, A326511.
Row sums give A091980(n+1).
T(2n,n) gives A309050.
Rows reversed converge to A000108.
Sequence in context: A008284 A114088 A208245 * A274190 A322596 A037306
KEYWORD
nonn,tabl
AUTHOR
Alois P. Heinz, Jul 09 2019
STATUS
approved