OFFSET
1,4
COMMENTS
Ordinal transform of f, where f(1) = 0 and f(n) = A303753(n) for n > 1.
LINKS
Antti Karttunen, Table of n, a(n) for n = 1..65537
MATHEMATICA
b[_] = 0;
f[n_] := If[n == 1, 0, A303753[n]];
Clear[b]; b[_] = 0;
a[n_] := a[n] = With[{t = f[n]}, b[t] = b[t]+1];
Array[a, 105] (* Jean-François Alcover, Dec 19 2021 *)
PROG
(PARI)
up_to = 65537;
ordinal_transform(invec) = { my(om = Map(), outvec = vector(length(invec)), pt); for(i=1, length(invec), if(mapisdefined(om, invec[i]), pt = mapget(om, invec[i]), pt = 0); outvec[i] = (1+pt); mapput(om, invec[i], (1+pt))); outvec; };
A051953(n) = (n - eulerphi(n));
v303753 = ordinal_transform(vector(up_to, n, A051953(n)));
Aux303754(n) = if(1==n, 0, v303753[n]);
v303754 = ordinal_transform(vector(up_to, n, Aux303754(n)));
A303754(n) = v303754[n];
CROSSREFS
KEYWORD
nonn
AUTHOR
Antti Karttunen, Apr 30 2018
STATUS
approved