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A302098
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Number of prime factors (with multiplicity) of generalized Fermat number 14^(2^n) + 1.
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1
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OFFSET
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0,1
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COMMENTS
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LINKS
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FORMULA
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EXAMPLE
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b(n) = 14^(2^n) + 1
Complete factorizations:
b(0) = 3*5
b(1) = 197
b(2) = 41*937
b(3) = 17*5393*16097
b(4) = 193*11284732320255809
b(5) = 7489*1204905857*1667461121*315256811699009
b(6) = 8633886977*P64
b(7) = 257*100497382788383295179961898289105815085380571534081*P95
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PROG
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(PARI) a(n) = bigomega(14^(2^n)+1)
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CROSSREFS
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KEYWORD
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nonn,hard,more
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AUTHOR
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STATUS
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approved
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