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A300357 a(n) is the smallest number whose number of divisors is the n-th odd square. 2
1, 36, 1296, 46656, 44100, 60466176, 2176782336, 1587600, 2821109907456, 101559956668416, 57153600, 131621703842267136, 1944810000, 341510400, 6140942214464815497216, 221073919720733357899776, 74071065600, 70013160000, 10314424798490535546171949056 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,2
COMMENTS
Equivalently, a(n) is the smallest number having exactly (2n-1)^2 divisors. (Since the number of divisors is odd, each term is necessarily a square.)
Subsequence of A025487.
Bisection of A061707. - Michel Marcus, Mar 04 2018
LINKS
EXAMPLE
For n=2, the n-th odd square is (2n-1)^2 = (2*2-1)^2 = 9. Each number having exactly 9 divisors is of one of the forms p^8 or p^2*q^2 where p and q are distinct primes. The smallest number of the form p^8 is 2^8=256, but the smallest of the form p^2*q^2 is 2^2*3^2 = 36, so a(2)=36.
For n=5, the n-th odd square is 81. Each number having exactly 81 divisors is of one of the forms p^80, p^26*q^2, p^8*q^8, p^8*q^2*r^2, or p^2*q^2*r^2*s^2, where p, q, r, and s are distinct primes. Since the exponents in each form as written above are in nonincreasing order, the smallest number of each form is obtained by assigning the first few primes in increasing order to p, q, r, and s, i.e., p=2, q=3, r=5, and s=7. The smallest resulting number is 2^2*3^2*5^2*7^2 = 44100, so a(5)=44100.
CROSSREFS
Cf. A000005 (number of divisors of n), A000290 (squares), A016754 (odd squares), A005179 (smallest number with exactly n divisors), A025487 (products of primorials), A061707.
Sequence in context: A224352 A224194 A224011 * A009980 A041613 A255821
KEYWORD
nonn
AUTHOR
Jon E. Schoenfield, Mar 03 2018
STATUS
approved

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Last modified April 25 04:42 EDT 2024. Contains 371964 sequences. (Running on oeis4.)