login
The OEIS is supported by the many generous donors to the OEIS Foundation.

 

Logo
Hints
(Greetings from The On-Line Encyclopedia of Integer Sequences!)
A298267 a(n) is the maximum number of heptiamonds in a hexagon of order n. 1
0, 3, 7, 13, 21, 30, 42, 54, 69, 85, 103, 123, 144, 168, 192, 219, 247, 277, 309, 342, 378, 414, 453, 493, 535, 579, 624, 672, 720, 771, 823, 877, 933, 990, 1050, 1110, 1173, 1237, 1303, 1371, 1440, 1512, 1584, 1659, 1735, 1813, 1893, 1974, 2058, 2142 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,2
COMMENTS
There are 24 heptiamonds.
It would be nice if this idea could be generalized to state that the hexagon can contain the maximum number of polyiamonds of any given size.
LINKS
Craig Knecht, Peripheral Buildouts.
Craig Knecht, Proof notes.
FORMULA
a(n) = floor((6*n^2)/7).
Conjectures from Colin Barker, Jan 20 2018: (Start)
G.f.: x*(1 + x)*(3 - 2*x + 4*x^2 - 2*x^3 + 3*x^4) / ((1 - x)^3*(1 + x + x^2 + x^3 + x^4 + x^5 + x^6)).
a(n) = 2*a(n-1) - a(n-2) + a(n-7) - 2*a(n-8) + a(n-9) for n>8.
(End)
MATHEMATICA
Array[Floor[(6 #^2)/7] &, 50] (* Michael De Vlieger, Jan 20 2018 *)
CROSSREFS
Cf. A033581 (The number of triangles in a hexagon), A291582 (hexiamond tiling).
Sequence in context: A077853 A256588 A025721 * A235532 A195020 A169627
KEYWORD
nonn
AUTHOR
Craig Knecht, Jan 15 2018
STATUS
approved

Lookup | Welcome | Wiki | Register | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Style Sheet | Transforms | Superseeker | Recents
The OEIS Community | Maintained by The OEIS Foundation Inc.

License Agreements, Terms of Use, Privacy Policy. .

Last modified April 25 05:18 EDT 2024. Contains 371964 sequences. (Running on oeis4.)