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A294862
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Solution of the complementary equation a(n) = a(n-2) + b(n-2) + 2, where a(0) = 1, a(1) = 2, b(0) = 3, and (a(n)) and (b(n)) are increasing complementary sequences.
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3
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1, 2, 6, 8, 13, 17, 24, 29, 37, 43, 53, 60, 71, 80, 92, 102, 115, 126, 140, 153, 168, 182, 198, 214, 231, 248, 266, 284, 303, 322, 343, 363, 385, 406, 429, 452, 476, 500, 525, 550, 576, 602, 629, 656, 685, 713, 743, 772, 803, 833, 866, 897, 931, 963, 998
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OFFSET
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0,2
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COMMENTS
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The increasing complementary sequences a() and b() are uniquely determined by the titular equation and initial values. See A294860 for a guide to related sequences.
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LINKS
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EXAMPLE
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a(0) = 1, a(1) = 2, b(0) = 3
b(1) = 4 (least "new number")
a(2) = a(0) + b(0) + 2 = 6
Complement: (b(n)) = (3, 4, 5, 7, 9, 10, 11, 12, 14, 15, 16, ...)
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MATHEMATICA
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mex := First[Complement[Range[1, Max[#1] + 1], #1]] &;
a[0] = 1; a[1] = 2; b[0] = 3;
a[n_] := a[n] = a[n - 2] + b[n - 2] + 2;
b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]];
Table[a[n], {n, 0, 18}] (* A294862 *)
Table[b[n], {n, 0, 10}]
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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