

A292552


Nontotients of the form 10^k  2.


0



98, 998, 9998, 99998, 999998, 9999998, 99999998, 999999998, 9999999998, 99999999998, 999999999998, 9999999999998, 99999999999998, 999999999999998, 9999999999999998, 99999999999999998, 999999999999999998, 9999999999999999998, 99999999999999999998
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OFFSET

1,1


COMMENTS

There are no k for which (2^n)*(5^n)[p1*p2*...*pk]2[p1*p2*...*pk]=m[(p11)*(p21)*...*(pk1)].
Up to k = 60, the only totient of the form 10^k2 is obtained for k=1.  Giovanni Resta, Sep 20 2017
For 10^k2 with k > 1 to be a totient, it would have to be of the form (p1)*p^m for some odd prime p and m >= 2.  Robert Israel, Sep 20 2017


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KEYWORD

nonn


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STATUS

approved



