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A292473
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Square array read by antidiagonals downwards: A(n,k) = k-th prime p such that A001222(2^p-1) = n.
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0
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2, 3, 11, 5, 23, 29, 7, 37, 43, 157, 13, 41, 47, 173, 113, 17, 59, 53, 181, 151, 223, 19, 67, 71, 229, 163, 239
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OFFSET
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1,1
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COMMENTS
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A permutation of the prime numbers.
Is this the same as k-th prime p such that A001221(2^p-1) = n?
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LINKS
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EXAMPLE
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Array starts
2, 3, 5, 7, 13, 17, ....
11, 23, 37, 41, 59, 67, ....
29, 43, 47, 53, 71, 73, ....
157, 173, 181, 229, 233, 263, ....
113, 151, 163, 191, 251, 307, ....
223, 239, 359, 463, 587, 641, ....
....
A(2, 3) = 37, because the 3rd prime p such that 2^p-1 has 2 prime factors is 37, with 2^37-1 = 223 * 616318177.
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MATHEMATICA
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With[{s = Array[PrimeOmega[2^Prime@ # - 1] &, 50]}, Function[t, Function[u, Table[Prime@ u[[#, k]] &[n - k + 1], {n, Length@t}, {k, n, 1, -1}]]@ Map[PadRight[#, Length@ t] &, t]]@ Values@ KeySort@ PositionIndex@ s] // Flatten (* Michael De Vlieger, Sep 17 2017 *)
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CROSSREFS
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KEYWORD
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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