OFFSET
0,3
COMMENTS
This is equivalent to A195206, since a(n) = (#twos)-(#ones) = 10^n-2*(#ones) in the first 10^n entries of A000002.
For example, a(2) = 51 - 49 = (100 - 49) - 49 = 100 - 2*49 = 2 because there are 49 ones and 51 twos in the first 100 = 10^2 entries of A000002.
The entries in this sequence appear to be of order 10^(n/2), whereas the entries in A195206 are larger (of order 10^n).
This sequence is analogous to A289323; the difference is that the indices are powers of ten instead of powers of two.
FORMULA
a(n) = 10^n - 2*A195206(n).
EXAMPLE
CROSSREFS
KEYWORD
sign,more
AUTHOR
Richard P. Brent, Jul 07 2017
EXTENSIONS
Additional (20th) term from Richard P. Brent, Mar 01 2018
STATUS
approved