



3, 6, 9, 10, 13, 15, 17, 20, 21, 23, 24, 26, 27, 30, 32, 34, 36, 38, 40, 42, 45, 46, 48, 49, 51, 52, 54, 55, 57, 58, 60, 61, 63, 64, 67, 69, 71, 73, 75, 77, 79, 81, 83, 85, 87, 89, 91, 93, 95, 98, 99, 101, 102, 104, 105, 107, 108, 110, 111, 113, 114, 116
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internal format)



OFFSET

1,1


COMMENTS

Conjecture: a(n)/n > 5/3..., and 4/3 < 5/3  a(n)/n < 0 for n >= 1.


LINKS

Clark Kimberling, Table of n, a(n) for n = 1..10000


MATHEMATICA

z = 11; (* number of iterates *)
s = {0, 0}; w[0] = StringJoin[Map[ToString, s]];
w[n_] := StringReplace[w[n  1], {"00" > "0010", "01" > "011", "10" > "010"}]
TableForm[Table[w[n], {n, 0, 10}]]
st = ToCharacterCode[w[z]]  48 (* A289128 *)
Flatten[Position[st, 0]] (* A289129 *)
Flatten[Position[st, 1]] (* A289130 *)


CROSSREFS

Cf. A289128, A289129.
Sequence in context: A206284 A268328 A247575 * A188299 A187577 A111359
Adjacent sequences: A289127 A289128 A289129 * A289131 A289132 A289133


KEYWORD

nonn,easy


AUTHOR

Clark Kimberling, Jun 28 2017


STATUS

approved



