OFFSET
1,2
COMMENTS
Equally: square array A(n,k) = P(A046523(n), (n+k-1)/n) if n divides (n+k-1), 0 otherwise, read by descending antidiagonals as A(1,1), A(1,2), A(2,1), etc. Here P is a two-argument form of sequence A000027 used as a pairing function N x N -> N.
When viewed as a triangular table, this sequence packs the values of A046523(k) [which essentially stores the prime signature of k] and quotient n/k (when it is integral) to a single value with the pairing function A000027. The two "components" can be accessed with functions A002260 & A004736, which allows us to generate from this sequence (among other things) various sums related to the enumeration of aperiodic necklaces, because Moebius mu (A008683) obtains the same value on any representative of the same prime signature.
For example, we have:
and
Triangle A286249 has the same property.
LINKS
Antti Karttunen, Table of n, a(n) for n = 1..10585; the first 145 rows of triangle/antidiagonals of array
Eric Weisstein's World of Mathematics, Pairing Function
FORMULA
EXAMPLE
The first fifteen rows of triangle:
1,
2, 3,
4, 0, 3,
7, 5, 0, 10,
11, 0, 0, 0, 3,
16, 8, 5, 0, 0, 21,
22, 0, 0, 0, 0, 0, 3,
29, 12, 0, 14, 0, 0, 0, 36,
37, 0, 8, 0, 0, 0, 0, 0, 10,
46, 17, 0, 0, 5, 0, 0, 0, 0, 21,
56, 0, 0, 0, 0, 0, 0, 0, 0, 0, 3,
67, 23, 12, 19, 0, 27, 0, 0, 0, 0, 0, 78,
79, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 3,
92, 30, 0, 0, 0, 0, 5, 0, 0, 0, 0, 0, 0, 21,
106, 0, 17, 0, 8, 0, 0, 0, 0, 0, 0, 0, 0, 0, 21
(Note how triangle A286249 contains on each row the same numbers
in the same "divisibility-allotted" positions, but in reverse order).
---------------------------------------------------------------
In the following examples: a = this sequence interpreted as a one-dimensional sequence, T = interpreted as a triangular table, A = interpreted as a square array, P = A000027 interpreted as a two-argument pairing function N x N -> N.
---
a(7) = T(4,1) = A(1,4) = P(A046523(1),4/1) = P(1,4) = 1+(((1+4)^2 - 1 - (3*4))/2) = 7.
a(30) = T(8,2) = A(2,7) = P(A046523(2),8/2) = P(2,4) = (1/2)*(2 + ((2+4)^2) - 2 - 3*4) = 12.
PROG
(Scheme)
(define (A286247bi row col) (if (not (zero? (modulo (+ row col -1) row))) 0 (let ((a (A046523 row)) (b (quotient (+ row col -1) row))) (* (/ 1 2) (+ (expt (+ a b) 2) (- a) (- (* 3 b)) 2)))))
;; Alternatively, with triangular indexing:
(define (A286247tr n k) (if (not (zero? (modulo n k))) 0 (let ((a (A046523 k)) (b (/ n k))) (* (/ 1 2) (+ (expt (+ a b) 2) (- a) (- (* 3 b)) 2)))))
(Python)
from sympy import factorint
def T(n, m): return ((n + m)**2 - n - 3*m + 2)/2
def P(n):
f = factorint(n)
return sorted([f[i] for i in f])
def a046523(n):
x=1
while True:
if P(n) == P(x): return x
else: x+=1
def t(n, k): return 0 if n%k!=0 else T(a046523(k), n/k)
for n in range(1, 21): print [t(n, k) for k in range(1, n + 1)] # Indranil Ghosh, May 08 2017
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
Antti Karttunen, May 06 2017
STATUS
approved