OFFSET
1,2
COMMENTS
For any n>0, n and a(n) are coprime.
There is only one fixed point: a(1) = 1.
All terms are odd.
All terms > 1 have an even ancestor (if n > 1 then a(n) = a^i(2*j) for some i >= 0 and j > 0).
If n > 1, then a(n) > n.
This can be proved by induction, by considering u(n) = least odd term not seen among {a(1), ..., a(n-1)}, and noticing also that u(2*n) > 2*n.
The derived sequence b=(a+1)/2 is a permutation of the natural numbers.
The first terms of the orbit of 2 are: 2, 3, 5, 11, 23, 47, 97, 197, 401, 809, 1627, 3259, 61*107, 13063, 7*3733, 13*4021, 19*5503, 163*1283, 29*14423, 83*10079, 929*1801.
Conjecturally, a(n) ~ 2*n.
LINKS
Rémy Sigrist, Table of n, a(n) for n = 1..10000
Rémy Sigrist, PARI program for A285848
EXAMPLE
a(1) = 1 is appropriate.
a(2) must be coprime to 2, and differ from 1; a(2) = 3 is appropriate.
a(3) must be coprime to 3 and 2, and differ from 1 and 3; a(3) = 5 is appropriate.
a(4) must be coprime to 4, and differ from 1, 3 and 5; a(4) = 7 is appropriate.
CROSSREFS
KEYWORD
nonn
AUTHOR
Rémy Sigrist, Apr 27 2017
STATUS
approved
