OFFSET
1,2
COMMENTS
This sequence can always be extended with a multiple of 2310 = 2*3*5*7*11; after a term that has at least 5 distinct prime factors, we can extend the sequence with the least unused number; as there are infinitely many numbers with at least 5 distinct prime factors, this sequence is a permutation of the natural numbers (with inverse A285488).
Conjecturally, a(n) ~ n.
The first fixed points are: 1, 75, 295, 375, 1205, 1207, 1211, 6017, 19870, 19872, 19874, 19878, 19907, 19909.
LINKS
EXAMPLE
The first terms, alongside the primes p dividing a(n)*a(n+1), are:
n a(n) p
-- ---- --------------
1 1 2, 3, 5, 7, 11
2 2310 2, 3, 5, 7, 11
3 2 2, 3, 5, 7, 11
4 1155 2, 3, 5, 7, 11
5 4 2, 3, 5, 7, 13
6 1365 2, 3, 5, 7, 13
7 6 2, 3, 5, 7, 11
8 385 2, 3, 5, 7, 11
9 12 2, 3, 5, 7, 13
10 455 2, 3, 5, 7, 13
11 18 2, 3, 5, 7, 17
12 595 2, 5, 7, 11, 17
13 22 2, 3, 5, 7, 11
14 105 2, 3, 5, 7, 13
15 26 2, 3, 5, 11, 13
16 165 2, 3, 5, 7, 11
17 14 2, 3, 5, 7, 13
18 195 2, 3, 5, 7, 13
19 28 2, 3, 5, 7, 17
20 255 2, 3, 5, 17, 19
CROSSREFS
KEYWORD
nonn,look
AUTHOR
Rémy Sigrist, Apr 19 2017
STATUS
approved