login
A284169
a(n) is the least k such that sigma(binomial(m,k)) = sigma(binomial(m-1,k-1)) + sigma(binomial(m-1,k)) where m = A284168(n).
1
1, 2, 5, 5, 9, 3, 17, 13, 21, 10, 18, 6, 28, 32, 33, 26, 20, 27, 28, 19, 12, 41, 34, 42, 54, 25, 5, 28, 84, 22, 40, 5, 54, 44, 56, 25, 29, 86, 81, 89, 88, 134, 10, 71, 148, 69, 87, 27, 91, 92, 18, 128, 23, 51, 52, 153, 108, 202, 112, 138, 58, 201, 141, 162, 176, 77, 4
OFFSET
1,2
COMMENTS
Consider the triangle formed by replacing each m in Pascal's triangle with sigma(m). Then this sequence consists of the least column indices of the terms that are equal to the sum of its NW and N neighbors, as in a Pascal triangle.
EXAMPLE
Here is the triangle also described in A074801.
1,
1, 1,
1, 3, 1,
1, 4, 4, 1,
1, 7, 12, 7, 1,
1, 6, 18, 18, 6, 1,
On row index 3, we have 4 which is the sum of 1 and 3 its NW and N neighbors, this is A284168(1). The corresponding column index is 1, so a(1) = 1.
PROG
(PARI) T(n, k) = sigma(binomial(n, k));
isokT(n, k) = T(n-1, k-1) + T (n-1, k) == T(n, k);
isokn(n) = for (k=1, n-1, if (isokT(n, k), return(1)));
listak(nn) = for (n=1, nn, for (k=1, n-1, if (isokT(n, k), print1(k, ", "); break)));
CROSSREFS
KEYWORD
nonn
AUTHOR
Michel Marcus, Mar 21 2017
STATUS
approved