OFFSET
1,1
COMMENTS
In calculating terms of this sequence, use the convention that a(n)=0 for n<=-312.
Sequences like this are more naturally considered with the first nonzero term in position 1. But this sequence would then begin with 312 terms consisting entirely of alternating 4 and 312.
This sequence has exactly 6632 terms, since a(6632)=0 and computing a(6633) would refer to itself.
LINKS
Nathan Fox, Table of n, a(n) for n = 1..6632
MAPLE
MATHEMATICA
CROSSREFS
KEYWORD
nonn,fini,full
AUTHOR
Nathan Fox, Mar 19 2017
STATUS
approved
