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A282427
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Numbers k such that A282442(k) = ceiling(k/2) + 1.
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0
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1, 3, 7, 39, 47, 111, 959, 3319, 7407, 11967, 13007, 16239
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OFFSET
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1,2
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COMMENTS
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All terms are odd.
Proof: if A282442(2m) = m + 1, then the step of length m would have to have concluded on exactly the middle step, but a phase with step-length m cannot end on the middle step because the distance from the middle step to the top/bottom of the staircase is equal to m.
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LINKS
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CROSSREFS
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KEYWORD
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nonn,more
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AUTHOR
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STATUS
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approved
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