

A281941


Number of ways to write n as w^2 + x^2 + y^2 + z^2 with w and w + x + y + z both squares, where w,x,y,z are integers with x <= y <= z.


9



1, 2, 3, 5, 4, 1, 5, 2, 3, 4, 5, 1, 3, 1, 4, 2, 2, 1, 10, 5, 2, 2, 6, 1, 7, 7, 5, 7, 4, 3, 7, 1, 3, 12, 9, 4, 2, 2, 5, 3, 5, 5, 9, 10, 1, 5, 5, 1, 5, 3, 6, 8, 2, 4, 9, 4, 4, 8, 5, 3, 3, 4, 5, 3, 4, 5, 10, 4, 1, 5, 7, 1, 7, 10, 6, 8, 3, 2, 10, 2, 1
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OFFSET

0,2


COMMENTS

Conjecture: (i) a(n) > 0 for all n = 0,1,2,....
(ii) Any nonnegative integer n can be written as x^2 + y^2 + z^2 + w^2 with x  y + z and z + w both squares, where x,w are integers and y,z are nonnegative integers.
The author has proved that every n = 0,1,2,... is the sum of a fourth power and three squares. Y.C. Sun and the author have shown that any nonnegative integer can be written as w^2 + x^2 + y^2 + z^2 with w,x,y,z integers such that w + x + y + z is a square.


LINKS



EXAMPLE

a(5) = 1 since 5 = 0^2 + 0^2 + (1)^2 + 2^2 with 0 = 0^2 and 0 + 0 + (1) + 2 = 1^2.
a(23) = 1 since 23 = 1^2 + 2^2 + 3^2 + 3^2 with 1 = 1^2 and 1 + 2 + 3 + 3 = 3^2.
a(47) = 1 since 47 = 1^2 + (1)^2 + 3^2 + 6^2 with 1 = 1^2 and 1 + (1) + 3 + 6 = 3^2.
a(157) = 1 since 157 = 4^2 + (2)^2 + (4)^2 + 11^2 with 4 = 2^2 and 4 + (2) + (4) + 11 = 3^2.
a(284) = 1 since 284 = 9^2 + 3^2 + 5^2 + (13)^2 with 9 = 3^2 and 9 + 3 + 5 + (13) = 2^2.
a(628) = 1 since 628 = 9^2 + (5)^2 + (9)^2 + 21^2 with 9 = 3^2 and 9 + (5) + (9) + 21 = 4^2.


MATHEMATICA

SQ[n_]:=SQ[n]=IntegerQ[Sqrt[n]];
Do[r=0; Do[If[SQ[nx^4y^2z^2]&&SQ[x^2+(1)^i*y+(1)^j*z+(1)^k*Sqrt[nx^4y^2z^2]], r=r+1], {x, 0, n^(1/4)}, {y, 0, Sqrt[(nx^4)/3]}, {i, 0, Min[y, 1]}, {z, y, Sqrt[(nx^4y^2)/2]}, {j, 0, Min[z, 1]}, {k, 0, Min[Sqrt[nx^4y^2z^2], 1]}]; Print[n, " ", r]; Continue, {n, 0, 80}]


CROSSREFS



KEYWORD

nonn


AUTHOR



STATUS

approved



