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A278148
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Triangle T(n, m) giving in row n the numerators of the fractions for the Farey dissection of order n.
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1
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1, 1, 2, 1, 2, 3, 3, 1, 2, 2, 3, 5, 4, 1, 2, 2, 3, 3, 4, 5, 5, 7, 5, 1, 2, 2, 2, 3, 3, 4, 5, 5, 7, 9, 6, 1, 2, 2, 2, 3, 3, 3, 5, 4, 5, 7, 5, 7, 8, 7, 9, 11, 7, 1, 2, 2, 2, 2, 3, 3, 4, 5, 5, 4, 5, 7, 8, 7, 7, 8, 7, 9, 11, 13, 8, 1, 2, 2, 2, 2, 3, 3, 3, 3, 4, 5, 5, 7, 5, 6, 9, 7, 8, 7, 7, 8, 10, 11, 9, 11, 13, 15, 9
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OFFSET
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1,3
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COMMENTS
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In the Hardy reference one finds from the Farey fractions of order n >= 2 (see A006842/A006843) a dissection of the interval [1/(n+1), n/(n+1)] into A015614(n) = A005728(n) - 2 intervals J(n,j) = [l(n,j), r(n,j)], j = 1..A015614(n). They are obtained from three consecutive Farey fractions of order n: p(n,j-1)/q(n,j-1), p(n,j)/q(n,j), p(n,j+1)/q(n,j+1) by l(n,j) = p(n,j)/q(n,j) - 1/(q(n,j)*(q(n,j) + q(n,j-1))) = (p(n,j) + p(n,j-1))/(q(n,j) + q(n,j-1)) and r(n,j) = p(n,j)/q(n,j) + 1/(q(n,j)*(q(n,j) + q(n,j+1))) = (p(n,j) + p(n,j+1))/(q(n,j) + q(n,j+1)). (Hardy uses N for n, p/q - Chi_{p,q}'' for l (left) and p/q + Chi_{p,q}' for r (right)). For the second equations in l(n,j) and r(n,j) see the identities in Hardy-Wright, p. 23, Theorem 28.
Due to r(n,j) = l(n,j+1), for n >= 2 and j=1..A015614(n), it is sufficient to give for this Farey dissection of order n >= 2 only the two endpoints of the interval [1/(n+1), n/(n+1)] and the A015614(n) - 1 = A002088 - 2 = A005728(n) - 3 inner boundary points. The present table gives the numerators of these fractions. See the example section. For n = 1 we add the row 1/2 in accordance with A002088(1) = 1.
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REFERENCES
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G. H. Hardy, Ramanujan, AMS Chelsea Publ., Providence, RI, 2002, p. 121.
G. H. Hardy and E. M. Wright, An Introduction to the Theory of Numbers. 5th ed., Clarendon Press, Oxford, 2003, pp. 23, 29 - 31.
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LINKS
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FORMULA
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T(1, 1) = 1 and for n>= 2: T(n, 1) = 1, T(n, A002088(n)) = n and for m = 2..(A002088(n) - 1): T(n, m) = numerator(l(n,m)) = numerator( p(n,m)/q(n,m) - 1/(q(n,m)*(q(n,m) + q(n,m-1)))).
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EXAMPLE
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The triangle T(n, m) begins:
n\m 1 2 3 4 5 6 7 8 9 10 11 12 ...
1: 1
2: 1 2
3: 1 2 3 3
4: 1 2 2 3 5 4
5: 1 2 2 3 3 4 5 5 7 5
6: 1 2 2 2 3 3 4 5 5 7 9 6
...
n = 7: 1 2 2 2 3 3 3 5 4 5 7 5 7 8 7 9 11 7,
n = 8: 1 2 2 2 2 3 3 4 5 5 4 5 7 8 7 7 8 7 9 11 13 8,
n = 9: 1 2 2 2 2 3 3 3 3 4 5 5 7 5 6 9 7 8 7 7 8 10 11 9 11 13 15 9,
n = 10: 1 2 2 2 2 2 3 3 3 5 4 4 5 5 7 5 6 9 7 8 7 9 12 8 10 11 9 11 13 15 17 10.
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The fractions T(n,m)/A278149(n, m) begin:
n\m 1 2 3 4 5 6 7 8 9 10
1: 1/2
2: 1/3 2/3
3: 1/4 2/5 3/5 3/4
4: 1/5 2/7 2/5 3/5 5/7 4/5
5: 1/6 2/9 2/7 3/8 3/7 4/7 5/8 5/7 7/9 5/6
...
n = 6: 1/7 2/11 2/9 2/7 3/8 3/7 4/7 5/8 5/7 7/9 9/11 6/7,
n = 7: 1/8 2/13 2/11 2/9 3/11 3/10 3/8 5/12 4/9 5/9 7/12 5/8 7/10 8/11 7/9 9/11 11/13 7/8,
n = 8: 1/9 2/15 2/13 2/11 2/9 3/11 3/10 4/11 5/13 5/12 4/9 5/9 7/12 8/13 7/11 7/10 8/11 7/9 9/11 11/13 13/15 8/9,
n = 9: 1/10 2/17 2/15 2/13 2/11 3/14 3/13 3/11 3/10 4/11 5/13 5/12 7/16 5/11 6/11 9/16 7/12 8/13 7/11 7/10 8/11 10/13 11/14 9/11 11/13 13/15 15/17 9/10,
n = 10: 1/11 2/19 2/17 2/15 2/13 2/11 3/14 3/13 3/11 5/17 4/13 4/11 5/13 5/12 7/16 5/11 6/11 9/16 7/12 8/13 7/11 9/13 12/17 8/11 10/13 11/14 9/11 11/13 13/15 15/17 17/19 10/11.
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For n = 5 the actual intervals J(5,j), j= 1..9 are then:
[1/6, 2/9], [2/9, 2/7], [2/7, 3/8], [3/8, 3/7], [3/7, 4/7], [4/7, 5/8], [5/8, 5/7], [5/7, 7/9], [7/9, 5/6].
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CROSSREFS
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KEYWORD
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nonn,tabf,frac,easy
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AUTHOR
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STATUS
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approved
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