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A277368 Numbers such that the number of their divisors divide the sum of their aliquot parts. 1
1, 4, 10, 16, 25, 26, 34, 56, 58, 60, 64, 74, 81, 82, 90, 96, 100, 106, 120, 121, 122, 132, 146, 178, 184, 194, 202, 204, 216, 218, 226, 234, 248, 274, 276, 289, 298, 306, 312, 314, 346, 348, 362, 364, 376, 386, 394, 408, 440, 458, 466, 480, 482, 492, 504, 514 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,2
COMMENTS
If p is a prime such that p == 2 (mod 3) then p^2 is a term. Bateman et al. (1981) proved that the asymptotic density of this sequence is 0. - Amiram Eldar, Jan 16 2020
REFERENCES
Richard G. Guy, Unsolved Problems in Number Theory, 3rd ed., Springer, 2004, chapter 2, p. 76.
LINKS
Paul T. Bateman, Paul Erdős, Carl Pomerance and E.G. Straus, The arithmetic mean of the divisors of an integer, in Marvin I. Knopp (ed.), Analytic Number Theory, Proceedings of a Conference Held at Temple University, Philadelphia, May 12-15, 1980, Lecture Notes in Mathematics, Vol. 899, Springer, Berlin - New York, 1981, pp. 197-220, alternative link.
FORMULA
Solutions k to A000005(k) | A001065(k).
EXAMPLE
sigma(26) - 26 = 42 - 26 = 16, d(26) = 4 and 16 / 4 = 4.
MAPLE
with(numtheory): P:= proc(q) local n; for n from 1 to q do
if type((sigma(n)-n)/tau(n), integer) then print(n); fi; od; end: P(10^3);
MATHEMATICA
Select[Range@ 520, Mod[DivisorSigma[1, #] - #, DivisorSigma[0, #]] == 0 &] (* Michael De Vlieger, Oct 14 2016 *)
PROG
(PARI) isok(n) = ((sigma(n) - n) % numdiv(n)) == 0; \\ Michel Marcus, Oct 11 2016
(Magma) [k:k in [1..550]| (DivisorSigma(1, k)-k) mod DivisorSigma(0, k) eq 0]; // Marius A. Burtea, Jan 16 2020
CROSSREFS
Sequence in context: A366661 A271911 A322948 * A067274 A331081 A054901
KEYWORD
nonn,easy
AUTHOR
Paolo P. Lava, Oct 11 2016
STATUS
approved

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Last modified June 29 04:45 EDT 2024. Contains 373826 sequences. (Running on oeis4.)