OFFSET
1,1
COMMENTS
Such a number n must have at least three prime factors.
Are there infinitely many such numbers?
Among them are some Carmichael numbers: 1729, 75361, ... (A002997).
LINKS
Robert G. Wilson v, Table of n, a(n) for n = 1..1024
EXAMPLE
273 = 3 * 7 * 13, so phi(273) = 2 * 6 * 12 = 144 = 12^2 and lambda(273) = lcm(2, 6, 12) = 12, hence 273 is in the sequence.
Notice that phi(315) = 144 and lambda(315) = 12 also. However, mu(315) = 0 since 315 = 3^2 * 5 * 7, so for that reason 315 is not in the sequence.
MATHEMATICA
samePsiSqPhiQ[n_] := SquareFreeQ[n] && CarmichaelLambda[n]^2 == EulerPhi[n]; Select[1 + 2 Range@50000, samePsiSqPhiQ] (* Robert G. Wilson v, Apr 14 2017 *)
PROG
(PARI) is(n) = n>1 && n%2!=0 && issquarefree(n) && lcm(znstar(n)[2])^2==eulerphi(n) \\ Felix Fröhlich, Apr 22 2017
CROSSREFS
KEYWORD
nonn
AUTHOR
Thomas Ordowski and Altug Alkan, Apr 11 2017
STATUS
approved