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A276717
Least prime p < n^2 such that n^2 - p = x^k for some integers x > 1 and k > 1, or 1 if such a prime p does not exist.
2
1, 1, 5, 7, 17, 11, 13, 37, 17, 19, 89, 19, 41, 71, 29, 13, 73, 199, 37, 157, 41, 43, 17, 47, 113, 433, 53, 541, 809, 59, 61, 997, 89, 67, 1009, 71, 73, 113, 521, 79, 1553, 83, 1721, 1693, 89, 1873, 1697, 107, 97, 313, 101, 103, 761, 107, 109, 11, 113, 239, 1433, 2269
OFFSET
1,3
COMMENTS
The conjecture in A276711 implies that a(n) > 1 for all n > 2 except for n = 11^3 = 1331.
Note that for any integer n > 2 neither n^2 nor n^2 - 1 could be a prime.
EXAMPLE
a(2) = 1 since neither 2^2 - 2 nor 2^2 -3 has the form x^k with x and k integers greater than one.
a(3) = 5 since 5 is a prime with 3^2 - 5 = 2^2 but neither 3^2 - 2 nor 3^2 - 3 is a perfect power.
a(4913) = 23613281 since 23613281 is a prime with 4913^2 - 23613281 = 2^19, and 4913^2 - p is not a perfect power for any prime p < 23613281.
MATHEMATICA
Do[Do[If[IntegerQ[(n^2-Prime[j])^(1/k)], Print[n, " ", Prime[j]]; Goto[aa]], {j, 1, PrimePi[n^2-2]}, {k, 2, Log[2, n^2-Prime[j]]}]; Print[n, " ", 1]; Label[aa]; Continue, {n, 1, 60}]
CROSSREFS
KEYWORD
nonn
AUTHOR
Zhi-Wei Sun, Sep 16 2016
STATUS
approved