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 A274828 Integer part of the alternating n-th partial sum of the reciprocals of the successive prime gaps. 4
 1, 0, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 0, 0, 0, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,41 COMMENTS The graph of the first 15*10^3 terms looks like a realization of a random walk. It has an estimated fractal dimension of about 1.48 (with box counting method) which is closed to that of the random walk (3/2). LINKS Andres Cicuttin, Table of n, a(n) for n = 1..15000 FORMULA a(n) = floor(Sum_{i=1..n} ((-1)^(i - 1))/(prime(i+1)-prime(i))). a(n) = floor(Sum_{i=1..n} ((-1)^(i - 1))/A001223(i)). EXAMPLE The prime gaps (A001223) are 1, 2, 2, 4, 2, 4, 2, .... For n=7, the 7th partial sum is 1/1 - 1/2 + 1/2 - 1/4 + 1/2 - 1/4 + 1/2 = 3/2 so a(7) is the integer part of 3/2, which is 1. - Michael B. Porter, Jul 11 2016 MATHEMATICA Table[Floor@Sum[((-1)^(j - 1))/(Prime[j + 1] - Prime[j]), {j, 1, n}], {n, 1, 100}]; PROG (PARI) a(n) = floor(sum(i=1, n, ((-1)^(i-1))/(prime(i+1)-prime(i)))) \\ Felix FrÃ¶hlich, Jul 07 2016 CROSSREFS Cf. A001223, A217538. Sequence in context: A043543 A237684 A130634 * A257474 A257317 A163376 Adjacent sequences:  A274825 A274826 A274827 * A274829 A274830 A274831 KEYWORD sign AUTHOR Andres Cicuttin, Jul 07 2016 STATUS approved

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Last modified December 3 11:37 EST 2020. Contains 338900 sequences. (Running on oeis4.)