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 A274765 Cyclops numbers with circular digits {0,6,8,9}. 2
 0, 606, 608, 609, 806, 808, 809, 906, 908, 909, 66066, 66068, 66069, 66086, 66088, 66089, 66096, 66098, 66099, 68066, 68068, 68069, 68086, 68088, 68089, 68096, 68098, 68099, 69066, 69068, 69069, 69086, 69088, 69089, 69096, 69098, 69099, 86066, 86068, 86069, 86086, 86088, 86089, 86096, 86098, 86099 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS Intersection of A001743 and A134808. LINKS Kenny Lau, Table of n, a(n) for n = 1..20000 EXAMPLE 86069 is a member because it is cyclops (A134808) and each digit contains at least one loop (A001743). PROG (Python) import sys f = open('b274765.txt', 'w') i = 1 n = 0 a = [""] while True: ....for x in a: ........for y in a: ............f.write(str(i)+" "+x+"0"+y+"\n") ............i += 1 ............if i>20000: ................f.close() ................sys.exit() ....a = sum([[x+"6", x+"8", x+"9"] for x in a], []) # Kenny Lau, Jul 05 2016 (PARI) is_a001633(n) = #Str(n)%2==1 is_a001743(n) = #setintersect([1, 2, 3, 4, 5, 7], Set(digits(n)))==0 is_a134808(n) = if(n==0, return(1), if(n < 10, return(0), my(d=digits(n), x=1, y=#d); while(x < #d, if(d[x]==0, break); x++); while(y > 1, if(d[y]==0, break); y--); if(x==y && x==ceil(#Str(n)/2), return(1), return(0)))) is(n) = is_a001633(n) && is_a001743(n) && is_a134808(n) \\ Felix Fröhlich, Jul 05 2016 CROSSREFS Cf. A001633, A001742, A134808, A160561. Sequence in context: A250969 A265244 A228036 * A249524 A064250 A186818 Adjacent sequences:  A274762 A274763 A274764 * A274766 A274767 A274768 KEYWORD nonn,base,easy AUTHOR Kenny Lau, Jul 05 2016 STATUS approved

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Last modified December 1 20:47 EST 2021. Contains 349435 sequences. (Running on oeis4.)