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A273039
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Numbers n such that the following process converges to zero: x(0)=n, x(i+1) = x(i) XOR ror(x(i)) XOR rol(x(i)), see the Comments section for details.
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0
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0, 5, 6, 9, 24, 29, 34, 40, 43, 45, 48, 51, 54, 57, 65, 66, 68, 71, 75, 77, 80, 83, 86, 89, 90, 92, 101, 102, 111, 129, 130, 135, 139, 141, 153, 154, 159, 180, 189, 198, 204, 209, 216, 219, 226, 231, 232, 238, 257, 260, 263, 267, 272, 275, 277, 278, 282, 284, 297
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OFFSET
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1,2
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COMMENTS
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Numbers n such that the following process converges to zero: x(0)=n, x(i+1) = x(i) XOR ror(x(i)) XOR rol(x(i)), where XOR is the binary exclusive-or operator, ror(x)=A038572(x) is x rotated one binary place to the right, and similarly rol(x)=A006257(n) is x rotated one binary place to the left.
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LINKS
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EXAMPLE
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n=5: x(0)=5, x(1) = 5 xor 6 xor 3 = 0.
n=6: x(0)=6, x(1) = 6 xor 5 xor 3 = 0.
n=9: x(0)=9, x(1) = 9 xor 12 xor 3 = 6, x(2)=0.
n=10: x(0)=10, x(1) = 10 xor 5 xor 5 = 10, and x(i)=10 for i>1.
n=17: x(0)=17, x(1) = 17 xor 24 xor 3 = 10, and x(i)=10 for i>1.
So 5, 6, 9 are in the sequence, 10 and 17 are not.
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MATHEMATICA
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Select[Range[0, 300], Nest[BitXor[BitXor[#, FromDigits[ RotateRight[ IntegerDigits[#, 2]], 2]], FromDigits[ RotateLeft[ IntegerDigits[#, 2]], 2]] &, #, 120] == 0 &] (* Michael De Vlieger, May 14 2016 *)
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PROG
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(Python)
BL = len(bin(n))-2
return (n>>1) + ((n&1) << (BL-1))
BL = len(bin(n))-2
return (n*2) - (1<<BL) + 1
for n in range(1000):
X = n
Xs = []
while not (X in Xs):
Xs.append(X)
if X==0:
print str(n)+', ',
break
X = X ^ ROR(X) ^ ROL(X)
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CROSSREFS
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KEYWORD
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nonn,base
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AUTHOR
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STATUS
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approved
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