OFFSET
1,1
FORMULA
a(n) = A269332(n) / n.
PROG
(PARI) a(n) = my(m=2*n); while (sumdigits(m) <= n, m+=n); m/n; \\ Michel Marcus, Feb 24 2016
(Python)
from itertools import count
def A269333(n): return next(k for k in count(2) if sum(map(int, str(k*n)))>n) # Chai Wah Wu, Jul 25 2022
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Franklin T. Adams-Watters, Feb 24 2016
EXTENSIONS
More terms from Michel Marcus, Feb 24 2016
STATUS
approved