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A268878
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Breadth-first traversal of a binary tree in which the value at the n-th node is equal to ParentNode()*prime(n-1).
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1
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1, 2, 3, 10, 14, 33, 39, 170, 190, 322, 406, 1023, 1221, 1599, 1677, 7990, 9010, 11210, 11590, 21574, 22862, 29638, 32074, 84909, 91047, 118437, 123321, 164697, 171093, 182793, 189501, 1014730, 1046690, 1234370, 1252390, 1670290, 1692710, 1819630, 1889170
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OFFSET
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1,2
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COMMENTS
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2 and 3 are the only primes in the sequence.
Each node N of the tree is divisible only by its ancestors.
All the nodes in a subtree T of T0 are divisible by T's root value.
Given two nodes in the tree, N and M, the common ancestor in the tree is GCD(N,M) (greatest common divisor of N and M).
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LINKS
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Davide Aversa, Table of n, a(n) for n = 1..1000
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FORMULA
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Recursive formula: a(1) = 1, a(n) = prime(n-1)* a(floor(n/2)).
The formula derives from the definition and the parent's index formula of a generic binary tree.
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EXAMPLE
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For n=5, a(5) = prime(4)*a(floor(5/2)) = prime(4)*a(2) = prime(4)*prime(1)*a(floor(2/2)) = prime(4)*prime(1)*a(1) = 7*2*1 = 14.
The tree begins:
1
2 3
10 14 33 39
170 190 322 406 1023 1221 1599 1677
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PROG
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(Python)
def a(n):
# Recursive version, assuming there is a function "prime" that returns
# the n-th prime number.
if n == 0:
return 1
else:
return prime(n-1)*a(math.floor((n-1)/2))
(PARI) a(n) = if (n==1, 1, prime(n-1)* a(n\2)) \\ Michel Marcus, Feb 16 2016
(MAGMA) [n le 1 select 1 else NthPrime(n-1)* Self(Floor(n/2)): n in [1..60]]; // Vincenzo Librandi, Feb 17 2016
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CROSSREFS
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Sequence in context: A129315 A171126 A299205 * A194544 A348475 A075770
Adjacent sequences: A268875 A268876 A268877 * A268879 A268880 A268881
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KEYWORD
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nonn,easy,tabf
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AUTHOR
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Davide Aversa, Feb 15 2016
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STATUS
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approved
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