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A268710
Number of iterations of A268395 needed to reach zero from 2^n + 1: a(n) = A268708(2^n + 1).
4
1, 2, 3, 4, 6, 9, 15, 25, 41, 75, 134, 246, 428, 802, 1454, 2643, 4588, 8851, 16849, 32368, 60504, 117343
OFFSET
0,2
FORMULA
a(n) = A268708((2^n)+1).
PROG
(Scheme) (define (A268710 n) (A268708 (+ 1 (A000079 n))))
CROSSREFS
KEYWORD
nonn,more
AUTHOR
Antti Karttunen, Feb 11 2016
STATUS
approved