OFFSET
0,2
COMMENTS
Inspired by A255870.
LINKS
Colin Barker, Table of n, a(n) for n = 0..1000
Kival Ngaokrajang, Illustration of initial terms
Index entries for linear recurrences with constant coefficients, signature (3,-2,-1,1).
FORMULA
a(0) = 1, for n > 0, a(n) = a(n-1) + 5*(fibonacci(n+3)-2) or a(n) = a(n-1) + 5*A001911(n).
From Colin Barker, Oct 18 2015: (Start)
a(n) = 3*a(n-1)-2*a(n-2)-a(n-3)+a(n-4) for n>3.
G.f.: -(x^3+5*x^2+3*x+1) / ((x-1)^2*(x^2+x-1)).
(End)
a(n) = -14 + 2^(-1-n)*((25-11*sqrt(5))*(1-sqrt(5))^n + (1+sqrt(5))^n*(25+11*sqrt(5))) - 10*(1+n). - Colin Barker, Mar 12 2017
PROG
(PARI) {a=1; print1(a, ", "); for(n=1, 100, b=fibonacci(n+3)-2; a=a+5*b; print1 (a, ", "))}
(PARI) Vec(-(x^3+5*x^2+3*x+1)/((x-1)^2*(x^2+x-1)) + O(x^50)) \\ Colin Barker, Oct 18 2015
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Kival Ngaokrajang, Oct 17 2015
STATUS
approved
