A261416 Let b(k) denote A260273(k). It appears that for k >= 200, whenever b(k) just passes a power of 2, 2^m say, the successive differences b(k)-2^m converge to this sequence.

2, 5, 8, 11, 17, 20, 23, 29, 38, 43, 49, 54, 61, 70, 75, 81, 84, 87, 93, 102, 107, 114, 119, 128, 131, 136, 139, 145, 148, 151, 157, 167, 173, 180, 187, 196, 201, 206, 211, 218, 225, 230, 235, 244, 253, 262, 267, 273, 276, 279, 285, 294, 299, 305, 310, 317, 327, 333, 340, 343, 349, 358, 365, 372, 381

Offset

0,1

Comments

It would be nice to have an independent characterization of this sequence.

A partial answer: set a(0)=2, and for n>0, a(n) = A261281(a(n-1)). - N. J. A. Sloane, Sep 17 2015

Links

Table of n, a(n) for n=0..64.

Example

At k=200, b(k)=b(200)=1026 has just passed 2^10. The successive differences b(200+i)-2^10 (i>=0) beyond this point are 2, 5, 8, 11, 17, 20, 23, 29, 38, 43, 49, 54, 61, 70, 75, 81, 84, 87, 93, 102, 107, 114, 119, 128, 131, 136, 139, 145, 148, 151, 157, [165, ...], which are the first 31 terms of the present sequence.
At k=371, b(371)=2050, and the successive differences b(371+i)-2^11 are 2, 5, ..., 279, 285, ... giving the first 51 terms of the present sequence.

Crossrefs

Cf. A260273, A261281. For when A260273 just passes a power of 2, see A261396.

Sequence in context: A032765 A375298 A340931 * A340386 A300272 A352143

Adjacent sequences: A261413 A261414 A261415 * A261417 A261418 A261419

Keyword

nonn

Author

N. J. A. Sloane, Aug 25 2015

Status

approved