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A261307
a(n+1) = abs(a(n) - gcd(a(n), 7*n+6)), a(1) = 1.
2
1, 0, 20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0, 167, 166, 165, 164, 163, 162, 161, 160, 159, 158, 79, 78, 77, 76, 75, 74, 73, 72, 71, 70, 69, 68, 67, 66, 65, 64, 63, 62, 61, 60, 59, 58, 57, 56, 55, 54, 53, 52, 51, 50, 49, 48, 47, 46, 45, 44, 43, 42, 41, 40, 39, 38, 37, 36, 35
OFFSET
1,3
COMMENTS
It is conjectured that for all n > 2, a(n) = 0 implies that 7n+6 = a(n+1) is prime, cf. A186259. (This is the sequence {u(n)} mentioned there.)
LINKS
EXAMPLE
a(2) = a(1) - gcd(a(1),7+6) = 1 - 1 = 0.
a(3) = |a(2) - gcd(a(2),7*2+6)| = gcd(0,17) = 17 is prime.
a(33) = 158, thus a(6) = 158 - gcd(158,7*33+6) = 158 - 79 = 79.
MATHEMATICA
nxt[{n_, a_}]:={n+1, Abs[a-GCD[a, 7n+6]]}; NestList[nxt, {1, 1}, 80][[All, 2]] (* Harvey P. Dale, Apr 26 2017 *)
PROG
(PARI) print1(a=1); for(n=1, 99, print1(", ", a=abs(a-gcd(a, 7*n+6))))
CROSSREFS
KEYWORD
nonn
AUTHOR
M. F. Hasler, Aug 14 2015
STATUS
approved