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A260882
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Least prime p such that 2*prime(p*n)+1 = prime(q*n) for some prime q.
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2
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3, 47, 3, 13, 797, 89, 2269, 733, 7877, 53, 14683, 16267, 17167, 59951, 10067, 761, 94463, 12437, 124561, 71881, 52009, 6791, 10061, 47287, 10789, 19009, 4813, 23173, 27427, 18701, 23011, 44917, 17, 70937, 883, 727, 99079, 10531, 18749, 126541, 18121, 34807, 29873, 159473, 853, 165317, 80627, 159721, 8263, 411707
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OFFSET
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1,1
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COMMENTS
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Conjecture: a(n) exists for any n > 0. In general, if a > 1 and b are integers with a+b odd and gcd(a,b)=1, then for any positive integer n there are primes p and q such that a*prime(p*n)+b = prime(q*n).
This is a supplement to the conjecture in A260120. It implies that there are infinitely many Sophie Germain primes.
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LINKS
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EXAMPLE
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a(2) = 47 since 2*prime(47*2)+1 = 2*491+1 = 983 = prime(83*2) with 47 and 83 both prime.
a(199) = 2784167 since 2*prime(2784167*199)+1 = 2*12290086499+1 = 24580172999 = prime(5399231*199) with 2784167 and 5399231 both prime.
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MATHEMATICA
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f[n_]:=Prime[n]
PQ[p_, n_]:=PrimeQ[p]&&PrimeQ[PrimePi[p]/n]
Do[k=0; Label[bb]; k=k+1; If[PQ[2*f[n*f[k]]+1, n], Goto[aa], Goto[bb]]; Label[aa]; Print[n, " ", f[k]]; Continue, {n, 1, 50}]
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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