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%I #12 Jul 19 2015 09:00:29
%S 0,1,3,5,7,9,11,15,17,21,23,27,29,31,35,39,41,45,47,51,53,57,59,61,65,
%T 69,71,73,77,79,81,83,87,91,95,97,105,107,111,115,119,121,125,127,135,
%U 137,139,143,147,149,151,155,157,165,167,171,173,177,179,183,187,195,197,201,205,209,213,217,221,223,231,233,237,239,243,247,255,257,261,263,267,269,271,275,279,281,283,287,289,297,301,305
%N The second infinite sequence starting with a(0)=0 such that A(a(k)) = a(k-1) for all k>=1, where A(n) = n - A037445(n) (cf. A260084).
%C The second infinitary analog (after A260084) of A259934 (see comment there). Using Falcao's method (2015) one can prove that such an infinite sequence exists.
%C All the first differences are powers of 2 (A260123).
%C See also comment in A260084.
%F a(n) = A260084(n)/2.
%Y Cf. A037445, A259934, A260084, A260123.
%K nonn
%O 0,3
%A _Vladimir Shevelev_, Jul 17 2015
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