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A259698
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Triangle read by rows: T(n,k) = number of permutations without overlaps having k increasing runs.
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2
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1, 1, 1, 1, 2, 1, 1, 4, 4, 1, 1, 6, 10, 6, 1, 1, 10, 23, 22, 9, 1, 1, 14, 44, 61, 41, 12, 1, 1, 22, 87, 158, 148, 71, 16, 1, 1, 30, 151, 352, 436, 301, 114, 20, 1, 1, 46, 280, 791, 1210, 1092, 589, 175, 25, 1, 1, 62, 464, 1592, 2969, 3317, 2408, 1038, 256, 30, 1
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OFFSET
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2,5
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COMMENTS
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The sums s(n) = Sum_k k*T(n,k) give A259700.
Albert Sade in Sur les Chevauchements des Permutation (published by the author in French in 1949) gave the following example for determining the number of increasing runs in a permutation: 176852943 has 3 runs: 123 (left to right), 34567 (right to left), 789 (right to left).
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LINKS
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EXAMPLE
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Triangle begins:
1;
1, 1;
1, 2, 1;
1, 4, 4, 1;
1, 6, 10, 6, 1;
1, 10, 23, 22, 9, 1;
1, 14, 44, 61, 41, 12, 1;
1, 22, 87, 158, 148, 71, 16, 1;
1, 30, 151, 352, 436, 301, 114, 20, 1;
1, 46, 280, 791, 1210, 1092, 589, 175, 25, 1;
1, 62, 464, 1592, 2969, 3377, 2408, 1038, 256, 30, 1;
...
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PROG
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(PARI)
Overlapfree(v)={for(i=1, #v, for(j=i+1, v[i]-1, if(v[j]>v[i], return(0)))); 1}
Chords(u)={my(n=2*#u, v=vector(n), s=u[#u]); if(s%2==0, s=n+1-s); for(i=1, #u, my(t=n+1-s); s=u[i]; if(s%2==0, s=n+1-s); v[s]=t; v[t]=s); v}
Runs(v)={my(u=vector(#v), s=1); for(i=1, #v, u[v[i]]=i); for(i=2, #u-1, if(sign(u[i]-u[i-1])==sign(u[i]-u[i+1]), s++)); s}
row(n)={my(r=vector(n-1)); if(n>=2, forperm(n, v, if(v[1]<>1, break); if(Overlapfree(Chords(v)), r[Runs(v)]++))); r}
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CROSSREFS
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KEYWORD
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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