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A258336
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Least solution of the equation x' = x + p for increasing values of p, where x' is the arithmetic derivative of x and p is an odd prime. a(n)= -1 if no such solution exists.
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1
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18, 1554, 53922, 726, 1218, 3230934, 966, 798, 546, 462, 210, 330, 390, 510, 690, 870, 930, 1110, 1230, 1290, 748146, 1590, 1770, 2010, 2130, 2190, 10010, 2370, 2490, 2910, 3030, 3210, 3270, 325374, 16288662, 3810
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OFFSET
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2,1
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COMMENTS
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First possible values without solutions are a(130), a(311), a(328), a(403) ...
If they exist, a(38), a(51) > 7*10^11. a(40) = 53086075098, a(43) = 2205467286, a(59) = 1343266518. - Giovanni Resta, Jun 08 2015
a(130) > 5*10^13.
a(38) <= 6757220092414242, a(82) <= 60382338056274, a(86) <= 4904019996019293138, a(100) <= 20288582235746170309362, a(103) <= 103153074623970054, a(185) <= 359626712451821152206, a(236) <= 41507154995420198557374 and a(378) <= 19746050339765838.
a(51) = 49441344782046, a(70) = 487059258, a(88) = 701726466, a(91) = 2192479278, a(116) = 1835382005358, a(126) = 64331242458, a(133) = 2179114806, a(141) = 23383324866 and a(142) = 2175820746. (End)
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LINKS
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EXAMPLE
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a(2) = 18 because the second prime is 3 and the solutions of the equation x' = x + 3 are 18, 315, ... where 18 is the least one.
a(3) = 1554 because the third prime is 5 and the solutions of the equation x' = x + 5 are 1554, 27950, ... where 1554 is the least one.
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MAPLE
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with(numtheory); P:=proc(q) local b, c, n, p;
for c from 2 to q do b:=ithprime(c); for n from 1 to q do
if n+b=n*add(op(2, p)/op(1, p), p=ifactors(n)[2]) then print(n);
break; fi; od; od; end: P(10^9);
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PROG
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(PARI) der(n) = sum(i=1, #f=factor(n)~, n/f[1, i]*f[2, i]);
a(n) = {k=1; p=prime(n); while(der(k) != k+p, k++); k; } \\ Michel Marcus, Aug 28 2015
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CROSSREFS
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KEYWORD
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nonn,more
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AUTHOR
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STATUS
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approved
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