OFFSET
1,2
COMMENTS
Column 3 of A255604.
LINKS
Harvey P. Dale, Table of n, a(n) for n = 1..1000
FORMULA
a(n) = floor(5*n^2/(4*tan(Pi/5))), n >= 1.
MATHEMATICA
Table[IntegerPart[5*n^2/(4*Tan[Pi/5])], {n, 51}] (* Michael De Vlieger, Mar 18 2015 *)
With[{c=Sqrt[25+10*Sqrt[5]]/4}, Table[IntegerPart[c*n^2], {n, 60}]] (* Harvey P. Dale, Aug 17 2020 *)
PROG
(PARI){for(n=1, 100, a=floor(5*n^2/(4*tan(Pi/5))); print1(a, ", "))}
(PARI) my(c=25+10*quadgen(20)); a(n) = sqrtint(floor(c*n^4))>>2; \\ Kevin Ryde, May 07 2021
CROSSREFS
KEYWORD
nonn
AUTHOR
Kival Ngaokrajang, Feb 27 2015
STATUS
approved