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A254733
a(n) is the least k > n such that n divides k^3.
4
2, 4, 6, 6, 10, 12, 14, 10, 12, 20, 22, 18, 26, 28, 30, 20, 34, 24, 38, 30, 42, 44, 46, 30, 30, 52, 30, 42, 58, 60, 62, 36, 66, 68, 70, 42, 74, 76, 78, 50, 82, 84, 86, 66, 60, 92, 94, 60, 56, 60, 102, 78, 106, 60, 110, 70, 114, 116, 118, 90, 122, 124, 84
OFFSET
1,1
COMMENTS
A073353(n) <= a(n) <= 2*n. Any prime that divides n must also divide a(n), and because n divides (2*n)^3.
FORMULA
a(n) = n + A019555(n).
EXAMPLE
a(8) = 10 because 8 divides 10^3, but 8 does not divide 9^3.
MATHEMATICA
lkn[n_]:=Module[{k=n+1}, While[PowerMod[k, 3, n]!=0, k++]; k]; Array[lkn, 70] (* Harvey P. Dale, Nov 23 2024 *)
PROG
(Ruby)
def a(n)
(n+1..2*n).find { |k| k**3 % n == 0 }
end
(PARI) a(n)=for(k=n+1, 2*n, if(k^3%n==0, return(k)))
vector(100, n, a(n)) \\ Derek Orr, Feb 07 2015
CROSSREFS
Cf. A073353 (similar, with k^n).
Cf. A254732 (similar, with k^2), A254734 (similar, with k^4).
Cf. A019555 (similar without the restriction that a(n) > n).
Sequence in context: A060685 A073353 A254734 * A254732 A299541 A066820
KEYWORD
nonn,easy
AUTHOR
Peter Kagey, Feb 06 2015
STATUS
approved