OFFSET
1,1
FORMULA
a(n) = floor(2^((3/2)^(n-1))).
MATHEMATICA
Floor[RecurrenceTable[{a[1]==2, a[n]==a[n-1]^(3/2)}, a, {n, 1, 15}]]
Table[Floor[2^((3/2)^(n-1))], {n, 1, 15}]
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Vaclav Kotesovec, Jan 30 2015
STATUS
approved