OFFSET
1,2
COMMENTS
Numbers m such that (m^m + 3)/(m - 3) is an integer.
Most but not all terms are congruent to 4 modulo 6. - Robert G. Wilson v, Dec 19 2014
Note that m^m == 3^m (mod m-3). - Robert Israel, Dec 19 2014
LINKS
Robert G. Wilson v, Table of n, a(n) for n = 1..331
EXAMPLE
2 is in this sequence because (2^2 + 3)/(2 - 3) = -7 is an integer.
4 is in this sequence because (4^4 + 3)/(4 - 3) = 259 is an integer.
7 is not in the sequence because (7^7 + 3)/4 = 411773/2, which is not an integer.
MAPLE
select(t -> 3 &^t + 3 mod (t-3) = 0, [1, 2, $4..10^6]); # Robert Israel, Dec 19 2014
MATHEMATICA
fQ[n_] := Mod[PowerMod[n, n, n - 3] + 3, n - 3] == 0; Select[Range@ 1000000, fQ] (* Michael De Vlieger, Dec 13 2014; modified by Robert G. Wilson v, Dec 19 2014 *)
PROG
(Magma) [n: n in [4..50000] | Denominator((n^n+3)/(n-3)) eq 1];
(PARI) isok(n) = (n != 3) && (Mod(n, n-3)^n == -3); \\ Michel Marcus, Dec 13 2014
CROSSREFS
Cf. ...............Numbers n such that x divides y, where:
...x......y....k = 0.....k = 1.....k = 2......k = 3.......
(For x=n-1 and y=n^n+1, the only terms are 0, 2 and 3. - David L. Harden, Dec 28 2014)
KEYWORD
nonn
AUTHOR
Juri-Stepan Gerasimov, Dec 12 2014
EXTENSIONS
More terms from Michel Marcus, Dec 13 2014
STATUS
approved