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A249883
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T(n,k)=Number of length n+6 0..k arrays with no seven consecutive terms having the maximum of any three terms equal to the minimum of the remaining four terms
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14
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35, 805, 35, 7420, 1365, 35, 40740, 18390, 2335, 35, 161315, 136010, 46460, 4019, 35, 510965, 684585, 463880, 118638, 6949, 35, 1377040, 2644815, 2967275, 1599494, 304782, 12053, 35, 3284400, 8435180, 13967995, 12991337, 5545760, 785512, 20942
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OFFSET
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1,1
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COMMENTS
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Table starts
.35....805.....7420......40740......161315........510965........1377040
.35...1365....18390.....136010......684585.......2644815........8435180
.35...2335....46460.....463880.....2967275......13967995.......52655600
.35...4019...118638....1599494....12991337......74439217......331379292
.35...6949...304782....5545760....57148261.....398306829.....2092722780
.35..12053...785512...19280050...251933535....2134932975....13234666552
.35..20942..2027106...67100334..1111583581...11450986236....83742245992
.35..36396..5230332..233536170..4905139755...61427553360...529949953516
.35..63995.13575241..815743709.21698329172..330105978348..3358192453066
.35.112578.35268844.2851383464.96037899299.1774766437056.21288206931304
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LINKS
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FORMULA
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Empirical for row n:
n=1: [polynomial of degree 7]
n=2: [polynomial of degree 8]
n=3: [polynomial of degree 9]
n=4: [polynomial of degree 10]
n=5: [polynomial of degree 11]
n=6: [polynomial of degree 12]
n=7: [polynomial of degree 13]
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EXAMPLE
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Some solutions for n=3 k=4
..0....1....0....0....1....1....0....0....0....0....1....0....1....1....1....1
..1....2....2....2....2....2....0....2....2....0....1....2....0....0....1....2
..4....0....4....2....4....1....3....4....1....3....2....4....3....3....3....0
..1....1....0....0....1....2....3....4....3....4....4....3....3....4....4....4
..3....3....3....2....0....1....4....0....4....0....0....0....0....3....2....3
..4....3....1....3....4....2....0....2....4....4....3....1....0....0....3....0
..3....2....0....0....3....4....1....0....4....2....4....4....4....0....4....0
..0....0....0....0....4....1....0....0....2....0....4....0....2....2....2....1
..0....3....4....4....0....4....0....1....4....1....1....2....4....3....2....4
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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