

A248645


Number of lightyears in a parsec, prior to its redefinition in August 2015.


3



3, 2, 6, 1, 5, 6, 3, 7, 7, 7, 1, 4, 1, 8, 7, 9, 8, 2, 9, 0, 5, 5, 5, 0, 9, 7, 7, 2, 9, 9, 6, 7, 5, 1, 7, 9, 2, 3, 2, 7, 8, 2, 8, 7, 2, 3, 6, 0, 8, 2, 3, 8, 2, 8, 2, 5, 3, 2, 5, 2, 9, 2, 6, 4, 1, 3, 4, 4, 2, 5, 7, 7, 3, 6, 6, 8, 7, 3, 1, 0, 8, 5, 4, 2, 3, 7, 6, 0, 0, 0, 7, 5, 1, 1, 5, 3, 1, 4, 5
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OFFSET

1,1


COMMENTS

Light takes approximately 3.26 years to cross a parsec.
Like A248424, this is an algebraic integer of degree 86400.  M. F. Hasler, Oct 31 2014
Although the definition has changed, this sequence is preserved in the OEIS for historical reasons.  N. J. A. Sloane, Oct 14 2017


LINKS

Table of n, a(n) for n=1..99.
Wikipedia, Parsec.
Wikipedia, Lightyear


FORMULA

Equals A248424 / A213614.


EXAMPLE

3.261563777... light years.


PROG

(PARI) A248645=(A248424=149597870700/tan(Pi/180/3600))/A213614=9460730472580800 \\ Then use eval(select(x>x>".", Vec(Str(%)))) to get the sequence of digits. First, use \pX to get X digits. M. F. Hasler, Oct 31 2014


CROSSREFS

Cf. A163103, A213614, A217572, A248424, A292525.
Sequence in context: A244823 A286157 A016460 * A161826 A097887 A019761
Adjacent sequences: A248642 A248643 A248644 * A248646 A248647 A248648


KEYWORD

nonn,cons,easy


AUTHOR

Arkadiusz Wesolowski, Oct 10 2014


EXTENSIONS

Edited and more terms added by M. F. Hasler, Oct 31 2014
Name edited by Arkadiusz Wesolowski, Oct 14 2017


STATUS

approved



