OFFSET
1,1
COMMENTS
Row 2 of A248537
LINKS
R. H. Hardin, Table of n, a(n) for n = 1..210
FORMULA
Empirical: a(n) = a(n-1) -a(n-2) +a(n-4) +a(n-7) +a(n-8) -a(n-9) +a(n-10) -a(n-12) -a(n-13) -a(n-15) -a(n-16) +a(n-18) -a(n-19) +a(n-20) +a(n-21) +a(n-24) -a(n-26) +a(n-27) -a(n-28)
Empirical also a cubic polynomial plus a linear quasipolynomial with period 360, the first 12 being:
Empirical for n mod 360 = 0: a(n) = (11/4)*n^3 - (113/20)*n^2 + (97/10)*n + 1
Empirical for n mod 360 = 1: a(n) = (11/4)*n^3 - (113/20)*n^2 + (209/20)*n - (111/20)
Empirical for n mod 360 = 2: a(n) = (11/4)*n^3 - (113/20)*n^2 + (97/10)*n - (19/5)
Empirical for n mod 360 = 3: a(n) = (11/4)*n^3 - (113/20)*n^2 + (149/20)*n + (25/4)
Empirical for n mod 360 = 4: a(n) = (11/4)*n^3 - (113/20)*n^2 + (97/10)*n - (57/5)
Empirical for n mod 360 = 5: a(n) = (11/4)*n^3 - (113/20)*n^2 + (209/20)*n - (35/4)
Empirical for n mod 360 = 6: a(n) = (11/4)*n^3 - (113/20)*n^2 + (97/10)*n - (109/5)
Empirical for n mod 360 = 7: a(n) = (11/4)*n^3 - (113/20)*n^2 + (149/20)*n - (291/20)
Empirical for n mod 360 = 8: a(n) = (11/4)*n^3 - (113/20)*n^2 + (97/10)*n - 11
Empirical for n mod 360 = 9: a(n) = (11/4)*n^3 - (113/20)*n^2 + (209/20)*n + (257/20)
Empirical for n mod 360 = 10: a(n) = (11/4)*n^3 - (113/20)*n^2 + (97/10)*n - 3
Empirical for n mod 360 = 11: a(n) = (11/4)*n^3 - (113/20)*n^2 + (149/20)*n + (269/20)
EXAMPLE
Some solutions for n=6
..0....3....5....2....2....2....5....0....0....6....6....1....2....4....6....0
..1....5....6....3....2....2....4....6....3....1....0....5....3....5....2....6
..2....4....5....1....4....3....3....6....2....4....0....6....6....5....4....3
..1....0....4....6....0....5....4....4....3....5....2....4....1....6....4....3
..4....3....1....2....2....2....5....0....0....6....6....5....2....4....6....0
CROSSREFS
KEYWORD
nonn
AUTHOR
R. H. Hardin, Oct 08 2014
STATUS
approved