OFFSET
0,2
COMMENTS
This is the column k=1 sequence of the Riordan triangle A248156 without a leading zero.
LINKS
G. C. Greubel, Table of n, a(n) for n = 0..1000
Index entries for linear recurrences with constant coefficients, signature (-3,-3,-1).
FORMULA
O.g.f.: (1 - 2*x^2)/(1 + x)^3 = -2/(1 + x) + 4/(1 + x)^2 - 1/(1 + x)^3.
a(n) = (-1)^n*(4*(2*n+1) - (n+1)*(n+2))/2, n >= 0.
a(n) = -3*(a(n-1) + a(n-2)) - a(n-3), n >= 3 with a(0) = 1, a(1) = -3 and a(2) = 4.
From R. J. Mathar, Mar 13 2021: (Start)
a(n) = (-1)^(n+1)*A046691(n-5).
a(n) + a(n+1) = A248157(n+1). (End)
E.g.f.: (1/2)*(2 - 4*x - x^2)*exp(-x). - G. C. Greubel, May 30 2025
MATHEMATICA
Table[(-1)^n*(2+5*n-n^2)/2, {n, 0, 60}] (* G. C. Greubel, May 30 2025 *)
PROG
(Magma)
[(-1)^n*(2+5*n-n^2)/2: n in [0..60]]; // G. C. Greubel, May 30 2025
(Python)
def A248158(n): return (-1)**n*(2+5*n-n**2)//2
print([A248158(n) for n in range(51)]) # G. C. Greubel, May 30 2025
CROSSREFS
KEYWORD
sign,easy
AUTHOR
Wolfdieter Lang, Oct 05 2014
STATUS
approved
