OFFSET
0,1
COMMENTS
The vertical distance between the accumulation point and the outermost point of a golden spiral inscribed inside a golden rectangle with dimensions phi and 1 along the x and y axes, respectively (the horizontal distance is A176015). - Amiram Eldar, May 18 2021
The limiting frequency of the digit 1 in the base phi representation of real numbers in the range [0,1], where phi is the golden ratio (A001622) (Rényi, 1957). - Amiram Eldar, Mar 18 2025
This constant gives the linear asymptotic coefficient of the average number of basepairs in an RNA secondary structure on a number n of vertices tending to infinity (see Theorem 3 in Bu, Kauers, and Zeilberger). - Stefano Spezia, Feb 27 2026
REFERENCES
Steven R. Finch, Mathematical Constants, Cambridge University Press, 2003, Section 1.2 The Golden Mean, phi, p. 7.
Steven R. Finch, Mathematical Constants, Cambridge University Press, 2003, Section 5.12.1 Phase transitions in Lattice Gas Models, p. 347.
LINKS
Rodney J. Baxter, Hard hexagons: exact solution, Journal of Physics A: Mathematical and General, Vol. 13, No. 3 (1980), pp. L61-L70, alternative link.
P. S. Bruckman and I. J. Good, A Generalization of a Series of De Morgan with Applications of Fibonacci Type, The Fibonacci Quarterly, Vol. 14, No. 3 (1976), pp. 193-196.
AJ Bu, Manuel Kauers, and Doron Zeilberger, Statistical Analysis of Hairpins and BasePairs in RNA Secondary Structures, arXiv:2602.19255 [math.CO], 2026.
Hideyuki Ohtsuka, Problem H-922, Advanced Problems and Solutions, The Fibonacci Quarterly, Vol. 61, No. 3 (2023), p. 282; Solution to Problem Problem H-922, by Yunyong Zhang, ibid., Vol. 63, No. 1 (2025), pp. 126-127.
Alfréd Rényi, Representations for real numbers and their ergodic properties, Acta Math. Acad. Sci. Hungar., Vol.8, No. 3-4 (1957), pp. 477-493.
Eric Weisstein's MathWorld, Hard Hexagon Entropy Constant.
Wikipedia, Hard Hexagon Model.
FORMULA
Equals 1/(sqrt(5)*phi), where phi = (1+sqrt(5))/2 = A001622. - Vaclav Kotesovec, Nov 13 2014
Equals Sum_{n>=1} A000045(3^(n-1))/A000032(3^n) = Sum_{n>=1} A045529(n-1)/A006267(n). - Amiram Eldar, Dec 20 2018
Equals 1 - A242671. - Amiram Eldar, Mar 18 2025
Equals Sum_{n>=1} (4^n/A000032(2^n)^2)*Sum_{k=1..n} A000045(2^k)/4^k (Ohtsuka, 2023). - Amiram Eldar, Dec 16 2025
EXAMPLE
0.2763932022500210303590826331268723764559381640388474275729102754589479...
MATHEMATICA
RealDigits[(5 - Sqrt[5])/10, 10, 102] // First
CROSSREFS
KEYWORD
AUTHOR
Jean-François Alcover, Nov 12 2014
STATUS
approved
