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A243910
Least number k>0 such that 3^k contains exactly n different digits.
0
1, 3, 5, 7, 9, 13, 15, 24, 30, 39
OFFSET
1,2
EXAMPLE
3^7 = 2187 is the first power of 3 that contains 4 different digits. Thus a(4) = 7.
PROG
(PARI) a(n)=for(k=1, 10^3, st=2^k; if(#digits(st)>=n, c=0; for(i=0, 9, for(j=1, #digits(st), if(digits(st)[j]==i, c++; break))); if(c==n, return(k))))
n = 1; while(n<11, print1(a(n), ", "); n++)
CROSSREFS
Sequence in context: A191182 A177855 A003524 * A211136 A178653 A222314
KEYWORD
nonn,base,full,fini
AUTHOR
Derek Orr, Jun 14 2014
STATUS
approved