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A240007
Smallest k such that the number of groups of order k is equal to prime(n), or 0 if no such k exists.
0
4, 75, 8, 375, 140, 56, 675, 1029, 294, 1380, 0, 180, 420, 112, 120, 656, 6875, 312, 243, 3660, 0, 3612, 0, 4140, 6498, 0, 0, 0, 0, 810, 0, 1260, 792, 0, 0, 0, 0, 0, 1936, 0, 1456, 1320, 0, 0, 144, 1000, 1368, 0, 1404, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
OFFSET
1,1
COMMENTS
Smallest k such that A000001(k) = prime(n), or 0 if no such k exists.
It seems that there is no order for which the number of groups is 31, 59, 71, 73, 79, 83, 89, 97, 101, 103, 109, 127, 139,...
Above comment is incorrect. According to the Conway article, every n <= 10000000 is the number of groups of order k for some k. So all the 0 entries above are wrong, but we do not necessarily know the true value. - Eric M. Schmidt, Sep 14 2014
LINKS
John H. Conway, Heiko Dietrich and E. A. O'Brien, Counting groups: gnus, moas and other exotica, The Mathematical Intelligencer, Spring 2008, Volume 30, Issue 2, pp 6-15, doi:10.1007/BF02985731.
EXAMPLE
a(6)= 56 because prime(6) = 13 => there exists 13 groups of order 56.
MATHEMATICA
lst={}; Do[k=1; While[!FiniteGroupCount[k]==Prime[n], k++]; If[k==2048, AppendTo[lst, 0], AppendTo[lst, k]], {n, 1, 70}]; lst
CROSSREFS
KEYWORD
nonn
AUTHOR
Michel Lagneau, Mar 30 2014
EXTENSIONS
Values for 59, 71, 79, 89, and 97 filled in from Conway link by Eric M. Schmidt, Sep 14 2014
STATUS
approved